wolf_2020

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Sep 24, 2017
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  • What’s your method to get E036153289470F858562CC4DAA5359 from the complete nonce? What exactly are you doing to derive that? E036153289470F858562CC4DAA5359381246C709F6193B68367727D39D999F8F…

  • I get that, but I really want some simple math to understand this better. can anyone break down how LLL_nonce_leakage works? like, real easy math or something?

  • import olll import random import math import secp256k1 as ice G = ice.scalar_multiplication(1) N = ice.N # Secret key = x = (rns1 r1sn)-1 (snm1 s1mn s1sn(k1 kn)) # For most significant fix 128 bit leak at least 3 sig is…

  • @COBRAS @krashfire Can you provide an example of rsz if your code is accurate? Like, r=0x, s=0x, z=0x. And if two signatures match, how long should it take to find K nonce?

  • What adjustments do I need to make in LLL_nonce_leakage.py to achieve this? My output shows keys are being generated, but not the correct ones. What am I missing?

  • Here you go: R = 64c2e12a01585b692b28b3bfc172df41a865862719a45728298428bc790c48a7 S = 7e7597a8553fda5bb3ebf990a8671c009a9b25211e873ddaa834e64034c98a53 Z = c69268be9eabc84554c2f4905b3977502aa3d52f077bb51dd8cadb502e87b258…

  • How do you get Z from R and S? Got some examples here: R = 0xcabc3692f1f7ba75a8572dc5d270b35bcc00650534f6e5ecd6338e55355454d5 S = 0xf65bfc44435a91814c142a3b8ee288a9183e6a3f012b84545d1fe334ccfac25e Looking for the target…

  • Hey guys, I need some help with the S calculation. Here's the data I have: priv_publickey_XY = px: 0xbb6c1de01f36618ae05f7c183c22dfa8797e779f39537752c27e2dc045b0e694 py:…

  • Anyone got the RSZ value? I’m kinda lost here… r=0x s=0x z=0x Need to fill this in to move forward.